Final answer:
To solve the system of equations {3x-2y=10, 4x-3y=14}, you can use the method of substitution. Substitute x = (2y + 10)/3 from the first equation into the second equation and solve for y. Substitute y = -2 back into the first equation to solve for x.
Step-by-step explanation:
To solve the system of equations {3x - 2y = 10, 4x - 3y = 14}, you can use the method of substitution. Here are the steps:
- Start with the first equation: 3x - 2y = 10. Solve for x in terms of y: 3x = 2y + 10. Dividing both sides by 3, we get x = (2y + 10)/3.
- Substitute x = (2y + 10)/3 into the second equation: 4((2y + 10)/3) - 3y = 14. Simplify and solve for y: (8y + 40)/3 - 3y = 14. Multiply both sides by 3 to get rid of the fraction: 8y + 40 - 9y = 42. Combine like terms: -y + 40 = 42. Subtract 40 from both sides: -y = 2. Multiply by -1 to solve for y: y = -2.
- Substitute y = -2 back into the first equation to solve for x: 3x - 2(-2) = 10. Simplify: 3x + 4 = 10. Subtract 4 from both sides: 3x = 6. Divide by 3 to solve for x: x = 2.
As a result, the system of equations is solved and the solution is x = 2, y = -2.