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If there are 29 B1B1 individuals, 38 B1B2 individuals, and 72 B2B2 individuals, then what is the frequency of B1B1?

-20.8%

-17.4%

-15%

-72%

User Zaxter
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1 Answer

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Final answer:

The frequency of B1B1 individuals is calculated by dividing the number of B1B1 individuals by the total population, which is 29/139, or approximately 20.8%.

Step-by-step explanation:

The frequency of the B1B1 genotype in a population can be calculated by dividing the number of B1B1 individuals by the total number of individuals in the population. In this case, if there are 29 B1B1 individuals, 38 B1B2 individuals, and 72 B2B2 individuals, the total number of individuals is 29 + 38 + 72 = 139. Therefore, the frequency of B1B1 individuals is 29/139.

To find the percentage, multiply by 100, so the frequency percentage is (29/139) * 100, which is approximately 20.86%. Thus, the correct option for the frequency of B1B1 individuals is approximately 20.8%.

SUMUP all the final answer as points at last: There are a total of 139 individuals. The frequency of the B1B1 genotype is 29/139 = 0.2086 or 20.86%, which approximately equals 20.8%.

User Chrsan
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