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Consider the following generic reaction: a 2b→c 3d, with Δh = 170 kj. Determine the value of Δh for each of the following related reactions: 3a 6b→3c 9d?

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Final answer:

To find the ΔH for the reaction 3a + 6b → 3c + 9d, multiply the original ΔH of the reaction (170 kJ) by 3, yielding a ΔH of 510 kJ for the scaled-up reaction.

Step-by-step explanation:

The question asks about determining the value of ΔH for a scaled-up version of a chemical reaction. The original reaction is 2b → c + 3d, with ΔH = 170 kJ. For the related reaction which is scaled up by a factor of three, 3a + 6b → 3c + 9d, the ΔH value would also be scaled up by the same factor.

To calculate ΔH for the new reaction, you multiply the original ΔH by the factor by which the entire reaction was scaled up. In this case, the reaction is tripled, so you would multiply 170 kJ by 3. Therefore, ΔH for the reaction 3a + 6b → 3c + 9d would be 510 kJ.

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