Question

A rigid rod of length l= 1 m and mass m = 2.5 kg is attached to a pivot mounted d = 0.17 m from one end. The rod can rotate in the vertical plane and is influenced by gravity. What is the period for small oscillations of the pendulum shown?

Answer 1

The period for small oscillations of the pendulum is approximately 2.01 seconds.

Step-by-step explanation:

To find the period of small oscillations of the pendulum, we can use the formula:

T = 2π√l/g

where T is the period, l is the length of the pendulum, and g is the acceleration due to gravity.

In this case, the length of the pendulum is 1 m and the acceleration due to gravity is approximately 9.8 m/s². Plugging in these values, we get:

T = 2π√1/9.8 ≈ 2π×0.32 ≈ 2.01 s

Therefore, the period for small oscillations of the pendulum is approximately 2.01 seconds.