Final answer:
Approximately 2.059 kcal of heat must be added to melt 85.5 g of platinum using the formula q = n×Δh, with the molar heat of fusion and the number of moles calculated based on the platinum's mass and molar mass.
Step-by-step explanation:
The question is asking how much heat (q) is required to melt 85.5 g of platinum at its melting point, given its molar heat of fusion is 4.700 kcal/mol. To find this, we need to calculate the number of moles (n) of platinum, then use the formula q = n×Δh.
First, we calculate the number of moles of platinum:
n = mass(g) / molar mass(g/mol)
Platinum has a molar mass of approximately 195.08g/mol.
n = 85.5g / 195.08g/mol ≈ 0.438 mol
Now we apply the formula to find the heat (q) required to melt the platinum:
q = n×Δh
q = 0.438 mol × 4.700 kcal/mol ≈ 2.059 kcal
Therefore, to melt 85.5 g of platinum at its melting point, approximately 2.059 kcal of heat must be added.