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Monica has ___ and ___ bills in her wallet with a total value of ___. If she had one more bill, she would have just as many ___ and ___ bills combined. She has ___ bills in total. How many of each type of bill does she have?

User BCsongor
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1 Answer

4 votes

Final answer:

The solution involves a decimal for the number of $5 bills, which seems inconsistent with the problem's context of whole numbers. Please double-check the values provided in the problem or let me know if there are any additional details or constraints.

Step-by-step explanation:

Let's denote the number of $1 bills as x, the number of $5 bills as y, and the number of $10 bills as z.

The given information can be translated into equations:

1. The total value of the bills is $96:

1x + 5y + 10z = 96

2. If she had one more $1 bill, she would have just as many $1 bills as $5 and $10 bills combined:

(x + 1) = (y + z)

3. She has a total of 23 bills:

x + y + z = 23

Now, let's solve this system of equations:

From the third equation, we can express x in terms of y and z:

x = 23 - y - z

Substitute this expression for x into the first two equations:

1. (23 - y - z) + 5y + 10z = 96

2. (23 - y - z + 1) = (y + z)

Now simplify and solve these equations.

1. -y + 9z = 70

2. -y - z = -23

Now, solve for y and z. You can use various methods, such as substitution or elimination. In this case, I'll use elimination:

Multiply the second equation by 9 so that the coefficients of y in both equations will cancel each other when summed:

1. -y + 9z = 70

2. -9y - 9z = -207

Now, sum the equations:

-y + 9z + (-9y - 9z) = 70 + (-207)

Simplify:

-10y = -137

Divide by -10 to solve for y:

y = 137 / 10

This doesn't result in a whole number of bills, which contradicts the given information. It's possible that there may be a mistake in the problem statement or in the values provided.

Please double-check the information, and if there's any clarification or additional information, feel free to provide it so that I can assist you further.

User Felix Yan
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