Final answer:
The question involves calculating the efficiency of a pump that has increased water pressure, considering negligible heat loss and unchanged kinetic and potential energies.
Step-by-step explanation:
The student is asking about the efficiency of a pump that is increasing the water pressure without significant changes to temperature, kinetic energy, or potential energy. To determine the pump efficiency, we must understand that the work supplied by the pump goes into increasing the water's pressure. Because the heat loss is negligible and the kinetic and potential energies do not change, the pump's efficiency can be calculated by comparing the work done (in increasing pressure) versus the energy input into the pump.