Question

When 5.12 g of NaOH were dissolved in 51.55 g of water in a calorimeter at 24.5 °C, the temperature of the solution increased to 49.8 °C. Part C: Determine the heat given off by the dissolution of NaOH, qrxn in J (recall qrxn = –qH₂O). If this quantity is negative, ensure you include a "-" in your answer. Do not include units when typing your answer.

Answer 1

The heat given off by the dissolution of NaOH can be calculated using the equation qrxn = -qH₂O. To find qH₂O, we first need to calculate the heat absorbed by the water, qH₂O. We can use the equation q = mcΔT, where q is the heat absorbed, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. The heat given off by the dissolution of NaOH is -4,346.69 J.

Step-by-step explanation:

The heat given off by the dissolution of NaOH can be calculated using the equation qrxn = -qH₂O. To find qH₂O, we first need to calculate the heat absorbed by the water, qH₂O. We can use the equation q = mcΔT, where q is the heat absorbed, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature.

First, we need to calculate the heat absorbed by the water:

qH₂O = (51.55 g) × (4.18 J/g °C) × (49.8 °C - 24.5 °C)

qH₂O = 4,346.69 J

Since qrxn is equal to -qH₂O, the heat given off by the dissolution of NaOH is -4,346.69 J.