Final answer:
The total resistance of the circuit with two resistors in parallel and one resistor in series is approximately 10.38 ohms.
Step-by-step explanation:
In a combined circuit with two resistors in parallel and another resistor in series, the total resistance can be found by adding the resistances of the parallel resistors and the resistance of the series resistor. In this case, the resistances of the parallel resistors are 10 ohms and 14 ohms, so their total resistance is 1/((1/10) + (1/14)) = 5.38 ohms(approximately). The resistance of the series resistor is 5 ohms. Therefore, the total resistance of the circuit is 5.38 + 5 = 10.38 ohms (approximately).