140k views
1 vote
At a school fair, there are different games to play that each require 6 tickets to play. Jordan wants a bag of popcorn that requires 20 tickets and to use the rest of the tickets to play games. Jordan has 104 tickets. Write an inequality using the values above to represent the situation, where 'x' is the number of games Jordan plays.

User Mbeasley
by
7.5k points

1 Answer

5 votes

Final answer:

Jordan can play at most 14 games at the school fair after getting a bag of popcorn with his 104 tickets since each game requires 6 tickets and the popcorn requires 20 tickets.

Step-by-step explanation:

Jordan has 104 tickets and wants to use 20 tickets to get a bag of popcorn. Since each game requires 6 tickets to play, we can represent the situation with an inequality. Let x represent the number of games Jordan plays. The inequality will be 6x + 20 ≤ 104, which accounts for the tickets used for popcorn and games. To solve for the maximum number of games Jordan can play, we subtract the 20 tickets for the popcorn from the total tickets Jordan has, which is 104, giving us 84 tickets available for games. Then we divide 84 by the number of tickets required per game, which is 6.So, we have the inequality 6x ≤ 84. Dividing both sides by 6, we find that x ≤ 14. Therefore, Jordan can play at most 14 games after getting the popcorn.

User Agconti
by
7.9k points