Question

At a certain temperature, 0.940 mol so3 is placed in a 3.00 l container. 2 so��� (g) = 2 so���(g) o���(g) at equilibrium, 0.100 mol o��� is present. Calculate the value of Kc.

Answer 1

The value of the equilibrium constant, Kc, for the given reaction is 3.025.

Step-by-step explanation:

The equilibrium constant, Kc, for the reaction 2SO2(g) + O2(g) = 2SO3(g) can be calculated using the concentrations of the reactants and products at equilibrium. According to the given information, the concentrations are [SO2] = 0.90 M, [O2] = 0.35 M, and [SO3] = 1.1 M. The equilibrium constant expression for this reaction is:

Kc = [SO3]^2 / ([SO2]^2 * [O2])

Substituting the given values into the expression:

Kc = (1.1)^2 / ((0.90)^2 * 0.35)

Calculating the value:

Kc = 3.025