In a direct variation between Y and X (Y = kX), with given values Y = 6 when X = 30, the constant of variation (k) is found to be
. Substituting X = 15, we find Y = 3.
When Y varies directly with X, the relationship can be expressed as Y = kX, where k is the constant of variation.
To find k, we can use the given values when Y = 6 and X = 30:
![\[6 = k * 30\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/v74skq9vkc97rrdha2y0ymo81hy222ekcb.png)
Now, solve for k:
![\[k = (6)/(30) = (1)/(5)\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/o9m7m2yazaqfk7ormzu56sa601k6fmpy55.png)
Now that we have the constant of variation k, we can use it to find Y when X = 15:
![\[Y = (1)/(5) * 15 = 3\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/140dpvufljxxcgi4bvtywtmfs60sbz32tm.png)
Therefore, when X = 15, Y = 3.