Question

If 100 grams of water is to be heated from 24.0°C to 100.0°C to make a cup of tea, how much heat must be absorbed? The specific heat of water is 4.184 J/g∙°C

Solve the problem and show your work.

Answer 1

76*

Step-by-step explanation:

Answer 2

Q= 31,798.4

Step-by-step explanation:

You would use the specific heat formula which is Q=mCΔt

m(mass)=100

C(Specific heat capacity)= 4.184

Δt(change in temperature)=24-100=-76 or just 76 in this case

so Q=(100)(4.184)(76)=

418.4(76)=31,798.4

Therefore the missing value Q(heat lost or gained) equal 31,798.4

Hope that helped! xoxo