Final answer:
For achieving asymmetric encryption with 10 participants, where each has 2 keys (1 public, 1 private), a total of 20 encryption keys are needed.
Step-by-step explanation:
The question pertains to the concept of asymmetric encryption, a key component of cryptography. In an asymmetric algorithm, each participant has two keys: a public key and a private key. The public key can be shared with anyone, while the private key is kept secret. For 10 participants to fully implement an asymmetric algorithm, each person needs a pair of keys. Therefore, the total number of keys required is 20 (10 pairs of two).
To illustrate, suppose there are 10 participants labeled A through J. Participant A needs a public key (Apub) and a private key (Apvt). This pattern repeats for all participants, resulting in 10 public keys and 10 private keys, summing up to a total of 20 keys.
The correct answer to how many encryption keys are required to fully implement an asymmetric algorithm with 10 participants is: B. 20.