Final answer:
To determine the number of molecules of carbon dioxide present in 2.36 mg of carbon tetrachloride, we need to calculate the number of moles of carbon tetrachloride and use the mole ratio between carbon tetrachloride and carbon dioxide. The number of molecules of carbon dioxide is approximately 9.20 x 10^20 molecules.
Step-by-step explanation:
The molar mass of carbon tetrachloride (CCl4) is 153.82 g/mol. To determine the number of molecules of carbon dioxide (CO2) present in 2.36 mg of carbon tetrachloride, we need to convert the mass of carbon tetrachloride to moles and then use the mole ratio between carbon tetrachloride and carbon dioxide.
First, we convert the mass of carbon tetrachloride to moles:
Mass of carbon tetrachloride = 2.36 mg
= 0.00236 g
Moles of carbon tetrachloride = mass / molar mass
= 0.00236 g / 153.82 g/mol
= 1.53 x 10-5 mol
Next, we use the mole ratio between carbon tetrachloride and carbon dioxide:
1 mol CCl4 : 1 mol CO2
Therefore, the number of molecules of carbon dioxide is equal to the number of molecules of carbon tetrachloride, which is approximately 9.20 x 1020 molecules.