Question

For the reaction n2o4(g)⇌2no2(g) , the value of k at 25∘c is 7.19×10−3 .calculate [n2o4] at equilibrium when [no2]=2.10×10−2mol/l .

Answer 1

The equilibrium concentration of N₂O₄ is calculated using the equilibrium constant K and the given concentration of NO₂. By solving the equilibrium expression K = [NO₂]² / [N₂O₄], we find that the equilibrium concentration of N₂O₄ is 6.13×10⁻¹ mol/L.

Step-by-step explanation:

The question involves calculating the equilibrium concentration of N₂O₄ when NO₂ is at a certain concentration, given the equilibrium constant K for the reaction at a particular temperature. The reaction is N₂O₄(g) ⇌ 2NO₂(g), and the equilibrium constant K at 25°C is given as 7.19×10⁻³. Given the concentration of NO₂ is 2.10×10⁻² mol/L, we can use the equation for the equilibrium constant K = [NO₂]² / [N₂O₄] to solve for the concentration of N₂O₄ at equilibrium.

To perform the computation:

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Therefore, the equilibrium concentration of N₂O₄ can be calculated as follows:

K = (2.10×10⁻²)² / x

7.19×10⁻³ = (2.10×10⁻²)² / x

7.19×10⁻³ = 4.41×10⁻³ / x

x = 4.41×10⁻³ / 7.19×10⁻³

x = 6.13×10⁻¹ mol/L

The equilibrium concentration of N₂O₄ is 6.13×10⁻¹ mol/L when NO₂ is at 2.10×10⁻² mol/L and K is 7.19×10⁻³ at 25°C.