Question

Four 1.5 v size d batteries are placed in a series circuit which is used to light a lamp. if one of the d batteries is removed, and the circuit remains complete, how would this affect the current in the circuit? (aks 10a, dok 1)

Answer 1

Removing one battery from a series of four 1.5 V batteries will reduce the total voltage from 6 V to 4.5 V and subsequently decrease the current flowing through the circuit.

Step-by-step explanation:

If four 1.5 V size D batteries are placed in a series circuit to light a lamp, the combined voltage supplied to the lamp is 6 V (1.5 V × 4). When one of the batteries is removed, and the circuit remains complete, it affects the current in the circuit. The total voltage would drop to 4.5 V (1.5 V × 3), which will reduce the current flowing through the circuit since the voltage available to push the current through the resistance is decreased.

Using Ohm's Law (V = IR), where V is the voltage, I is the current, and R is the resistance, if the voltage (V) decreases and the resistance (R) stays the same, the current (I) must also decrease.