Answer: 110 large drinks, and 120 small drinks.
Explanation:
Let's define the variables:
S = number of small drinks he sold
L = number of large drinks he sold
We know that each small drink costs $1.00 and each large drink costs $1.50
Then the total revenue will be:
S*$1.00 + L*$1.50
We know that:
- He sold a total of 230 drinks, this is written as:
S + L = 230
- The total revenue was $285, then:
S*$1.00 + L*$1.50 = $285
Then we have a system of equations:
S + L = 230
S*$1.00 + L*$1.50 = $285
To solve this system we first need to isolate one variable in one of the equations, i will isolate S in the first equation:
S = 230 - L
Now we can replace this in the other equation to get:
(230 - L)*$1.00 + L*$1.50 = $285
Now we can solve this for L.
$230 - L*$1.00 + L*$1.50 = $285
$230 + L*$0.50 = $285
L*$0.50 = $285 - $230 = $55
L*$0.50 = $55
L = $55/$0.50 = 110
So 110 large drinks were sold.
Then with the equation
S + L = 230
We can find the value of S.
S = 230 - 110 = 120
S = 120
120 small drinks were sold.