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Find a point on the y axis that is equidistant from p(4,8)andr(4,-2)

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Final answer:

To find the point on the y-axis equidistant from P(4,8) and R(4,-2), we can use the midpoint formula. The point (4, 3) is equidistant from P(4,8) and R(4,-2) on the y-axis.

Step-by-step explanation:

To find a point on the y-axis that is equidistant from P(4,8) and R(4,-2), we can use the formula for finding the midpoint between two points. The midpoint formula is:

(x,y) = ((x1 + x2)/2, (y1 + y2)/2)

In this case, since the x-coordinate of both points is 4, the x-coordinate of the midpoint will also be 4. To find the y-coordinate, we can average the y-coordinates of P and R:

(4, (8 + (-2))/2) = (4, 3)

Therefore, the point (4, 3) is equidistant from P(4,8) and R(4,-2) on the y-axis.

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