Final answer:
When a voltage of 5.50 V is applied to an 8.00 pF capacitor, it stores a charge of 44.00 picoCoulombs (pC).
Step-by-step explanation:
To find the charge stored when a voltage is applied to a capacitor, we can use the formula Q = C × V, where Q is the charge in coulombs (C), C is the capacitance in farads (F), and V is the voltage in volts (V). In the given example, if 5.50 V is applied to an 8.00 pF (picoFarads) capacitor, the stored charge would be:
Q = 8.00 pF × 5.50 V
= 8.00 × 10-12 F × 5.50 V
= 44.00 × 10-12 C
= 44.00 pC (picoCoulombs)
Therefore, the capacitor stores a charge of 44.00 picoCoulombs when a potential difference of 5.50 volts is applied to it.