Final answer:
Option C (10mL of 2.5 M FeCl₃) contains the greatest number of chloride ions. This is because for each unit of FeCl₃, three chloride ions are produced, resulting in a total of 0.075 moles of Cl⁻ in the solution.
Step-by-step explanation:
The question is related to determining which solution contains the greatest number of chloride ions. To answer this, we need to calculate the number of chloride ions in each of the provided options.
- For option B (50mL of 1.0 M CaCl₂), since every formula unit of CaCl₂ generates two chloride ions, the total chloride concentration would be 2 M. Thus, the number of moles of chloride ions is 50 mL * 2 M / 1000 mL/L = 0.1 moles of Cl⁻ ions.
- For option C (10mL of 2.5 M FeCl₃), every unit of FeCl₃ produces three chloride ions, resulting in a chloride concentration of 7.5 M (2.5 M * 3). The number of moles of chloride ions is 10 mL * 7.5 M / 1000 mL/L = 0.075 moles of Cl⁻ ions.
- For option D (25mL of 2.0 M NaCl), there is a 1:1 ratio of Na+ to Cl⁻, giving us 25 mL * 2.0 M / 1000 mL/L = 0.05 moles of Cl⁻ ions.
Comparing these numbers, option C (10mL of 2.5 M FeCl₃) contains the greatest number of chloride ions.