Final answer:
To calculate the mass of oxygen formed, we need to use stoichiometry. First, convert the given mass of dinitrogen monoxide to moles. Next, use the mole ratio between dinitrogen monoxide and oxygen to calculate the moles of oxygen formed. Finally, convert moles of oxygen to grams using the molar mass of oxygen.
Step-by-step explanation:
To solve this problem, we need to use stoichiometry. From the balanced chemical equation of the decomposition of dinitrogen monoxide, we can see that for every 2 moles of dinitrogen monoxide, 1 mole of oxygen gas is formed.
First, we need to convert the given mass of dinitrogen monoxide to moles. The molar mass of dinitrogen monoxide (N2O) is 44.02 g/mol, so 5.00 g of dinitrogen monoxide is equivalent to 0.1136 moles.
Since the ratio of dinitrogen monoxide to oxygen is 2:1, we can calculate the moles of oxygen formed by dividing the moles of dinitrogen monoxide by 2. Therefore, 0.1136 moles of dinitrogen monoxide will form 0.0568 moles of oxygen.
To convert moles of oxygen to grams, we use the molar mass of oxygen (O2), which is 32.00 g/mol. Multiplying the moles of oxygen by the molar mass, we find that 0.0568 moles is equal to 1.82 grams of oxygen.