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Given the point (6,0) and a slope of -5/6, what is the equation of the line?

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Final answer:

The equation of the line with a slope of -5/6 passing through the point (6,0) is y = (-5/6)x + 5.

Step-by-step explanation:

Given a point (6,0) and a slope of -5/6, the equation of the line can be found using the point-slope form of a line, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point the line passes through. Plugging in the point (6,0) and the slope -5/6, we get y - 0 = (-5/6)(x - 6). This simplifies to y = (-5/6)x + 5, which is the equation of the line in slope-intercept form, where the slope is -5/6 and the y-intercept is 5.

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