Final answer:
Jamar can have between 12 and 13 quarters along with his 16 dimes, so he holds no less than 28 coins and the total value does not exceed $5.05.
Step-by-step explanation:
Jamar has 16 dimes, which have a total value of $1.60 since each dime is worth $0.10. Since Jamar has no less than 28 coins, the minimum possible number of coins is 28. Subtracting the 16 dimes, Jamar could have at least 12 more coins, all of which could be quarters. We need to calculate the maximum number of quarters he could have without exceeding a total value of $5.05.
To find the maximum number of quarters, we consider Jamar's total amount without considering the dimes he already has, which is $5.05 - $1.60 = $3.45. Now, we divide this by the value of a quarter, which is $0.25, to find the maximum number of quarters he could have: $3.45 ÷ $0.25 = 13.8. Since Jamar cannot have a fraction of a coin, the maximum number of whole quarters he can have is 13.
Thus, Jamar can have between 12 and 13 quarters, along with his 16 dimes, to not hold less than 28 coins and not exceed a total value of $5.05.