Question

Is anyone able to solve this?

Answer 1

2.4

Explanation:

The bottom is a right triangle. You know the 2 legs, you need the hypotenuse.

`a^(2)` +
`b^(2)` =
`c^(2)`

`1^(2)` +
`1^(2)` =
`c^(2)`

1 + 1 =
`c^(2)`

2 =
`c^(2)`

`√(2)` =
`\sqrt{c^(2) }`

`\sqrt2` = c

Now we know the 2 legs for the larger triangle on top.

`a^(2)` +
`b^(2)` =
`c^(2)`

`√(2) ^(2)` +
`2^(2)` =
`c^(2)`

2 + 4 =
`c^(2)`

6 =
`c^(2)`

`√(6)` =
`\sqrt{c^(2) }`

`√(6)` = c

`√(6)` rounded to the tenths place is 2.4