Question

3. A box of mass (m) sits at rest on an inclined plane. A force (F) is applied perpendicular to the top of the box (down and to the left). What is the magnitude of the applied force (F) such that the normal force from the incline on the box is equal to the weight of the box

Answer 1

F = w(1 - cosθ)

Step-by-step explanation:

Box sits at rest → ∑y = 0

∑y = 0

N - F - w cosθ = 0

Given N = w

w - F - w cosθ = 0

F = w - w cos θ

F = w(1 - cosθ)