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PLEASE HELP QUICK 25 POINTS

Solve the following system of equations algebraically:
y = x² - 14x + 23
y=-3x + 5

User Nevenoe
by
2.9k points

1 Answer

11 votes
11 votes

Answer:

x=9, x=2

Explanation:

Since both expressions (x^2 - 14x + 23 and -3x+5) are equal to y, set those expressions equal to each other and solve for x.

x^2 - 14x + 23 = -3x + 5

subtract 5 from both sides

x^2 - 14x + 23 - 5 = -3x + 5 - 5

x^2 - 14x + 18 = -3x

add 3x to both sides

x^2 - 14x + 3x + 18 = -3x + 3x

x^2 - 11x + 18 = 0x

factor.

(x-9)(x-2) = 0

Because the product of these two things equals 0, we know that one of these terms must equal to zero.

x-9 = 0 or x-2 = 0

it can be either, so solve for both.

x-9 + 9 = 0 + 9 or x-2 + 2 = 0 + 2

x = 9 or x=2

User Colwin
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3.0k points