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A line has a slope of -1/7 and passes through the point (–7,–10). Write its equation in slope-intercept form.

User Georgiann
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Final answer:

The equation of the line with a slope of -1/7 passing through the point (-7, -10) can be written in slope-intercept form as y = -1/7*x + 9.

Step-by-step explanation:

To write the equation of a line with a slope of -1/7 that passes through the point (–7,–10), you can use the point-slope form of the equation of a line which is:

y - y₁ = m(x - x₁)

Where (x₁, y₁) is a point on the line, and m is the slope of the line. Substituting the given point and slope, you get the following equation:

y - (-10) = -1/7(x - (-7))

Simplifying this equation to slope-intercept form (y = mx + b) we get:

y = -1/7*x + (-1/7)*(-7) - 10

Which simplifies to:

y = -1/7*x + 9

User Renan Ivo
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