Question

A 73.9 kg water skier moving horizontally is pulled by a 105 n force at a 22.5 angle, while the water creates a 74.8 n force pulling directly backward.

Answer 1

The two water-skiers with a combined mass of 109 kg are pulled by a net force of 290 N. They will accelerate horizontally at a rate of 2.66 meters per second squared.

Step-by-step explanation:

The question pertains to calculating the acceleration of two water-skiers being pulled by a boat. To find the rate at which the skiers will accelerate, we apply Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass. The net force exerted on both skiers is 290 N, and the combined mass of the skiers is 48 kg + 61 kg, which equals 109 kg. Hence, their acceleration (a) can be calculated using the formula a = F/m, where F is the net force and m is the mass.

The acceleration would be calculated as:

• a = 290 N / 109 kg
• a = 2.66 m/s2

Therefore, the water-skiers will accelerate horizontally at a rate of 2.66 meters per second squared.