Final answer:
The magnitude of the frictional force on a sled with a boy sitting on it on a horizontal snowy surface is 1.404 N, and the tension in the rope, if pulled at constant speed, is also 1.404 N, matching the frictional force.
Step-by-step explanation:
The question inquires about the magnitude of the frictional force that a boy and his sled experience on a horizontal snowy surface and what the tension in the rope would be if pulled at a constant speed. To find the magnitude of the frictional force, we use the equation f k = μmg, where μ is the coefficient of friction, m is the total mass, and g is the acceleration due to gravity.
Since the boy and sled together weigh 65 N + 52 N = 117 N, and the coefficient of friction is 0.012, the frictional force is calculated as:
f k = 0.012 × 117 N = 1.404 N.
As the sled is pulled at a constant speed, the tension in the rope will be equal to the frictional force due to Newton's first law of motion. Therefore, the tension in the rope is also 1.404 N.