Question

You are going to launch a water balloon at 3.5 m/s at an angle of 35o how far does the object travel (δx)?

Answer 1

The object will travel approximately 1.33 meters.

Step-by-step explanation:

To calculate the horizontal distance traveled by an object launched at an angle, we can use the range formula. The range (δx) can be found using the equation:

δx = (vi2 * sin(2θ)) / g

where vi is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity.

Using the given values, we have:

δx = (3.5 m/s)2 * sin(2 * 35°) / 9.8 m/s2

Calculating this expression, we find that the object will travel approximately 1.33 meters (rounded to two decimal places).