Question

A car accelerates with a given force. Later the same car accelerates with 1/6 it's original acceleration and it now has 1.4 times its earlier mass.

(A) How does the car's later force compare with the its earlier force?
(B) If its earlier force is 1523 N, then what is the car's later force?

Answer 1

The later force of the car is (1.4/6) times the initial force. For an initial force of 1523 N, the later force would be approximately 356.066 N.

Step-by-step explanation:

When a car accelerates with a given force and later with 1/6 of its original acceleration while having 1.4 times its earlier mass, we can use Newton's second law, F = ma, to compare the forces. Initially, let the force be F and the acceleration a. Later, the force F' is associated with the acceleration a/6 and mass 1.4m.

Using the formula:

• Initial force: F = ma
• Later force: F' = 1.4m × (a/6) = (1.4/6) × F × a = (1.4/6) × F

Thus, the later force F' is (1.4/6) times the initial force F. If the initial force is 1523 N, the later force is:

F' = (1.4/6) × 1523 N = 356.066 N, rounded to three significant figures.