Question

An object of mass 10 kg is placed on a frictionless

incline of 25°. Deduce how many seconds it would
take to travel down a 5.0 m incline from rest.

Answer 1

Initial velocity = 0 m/s

Displacement = 5 m

Acceleration = 10cos25° = 9.06 m/s^2

time = ? (To be calculated)

Using, S = ut + at^2/2, we have

5 = 0(t)+9.06t^2/2

10/9.06 = t^2

t = 1.006 seconds