98.4k views
3 votes
Consider this product. (x²-4x-21)/(3x² 6x)*(x² 8x)/(x² 11x 24) which values are excluded values for the product?

User Dimitri
by
8.0k points

1 Answer

3 votes

Final answer:

The excluded values for the given product expression are 0, -2, -3, and -8, as setting the denominators of the expression equal to these values would result in division by zero, which is undefined.

Step-by-step explanation:

To find the excluded values for the product (x²-4x-21)/(3x²+6x) * (x²+8x)/(x²+11x+24), we need to consider the values of x for which the denominator is equal to zero, as division by zero is undefined in mathematics. The denominators in this expression are 3x²+6x and x²+11x+24. We set each denominator equal to zero and solve for x:

  • 3x² + 6x = 0
  • x² + 11x + 24 = 0

For the first denominator, we factor out an x:

x(3x + 6) = 0

Setting each factor equal to zero gives us x = 0 and x = -2 as excluded values. For the second denominator, we can factor it as (x+3)(x+8) = 0, giving us x = -3 and x = -8 as excluded values. Therefore, the excluded values for x are 0, -2, -3, and -8.

User Alexshr
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories