Final answer:
To find the sound intensity level in decibels for a sound intensity of 10 to the power of negative 6 watts per meter squared, use the formula β (dB) = 10 log10(I/I0), resulting in 60 decibels.
Step-by-step explanation:
To calculate the sound intensity level in decibels (dB) for a given sound intensity, you can use the formula β (dB) = 10 log10(I/I0), where I is the sound intensity and I0 is the reference sound intensity, typically 10-12 W/m2. For the given sound intensity of 10 to the power of negative 6 watts per meter squared, the calculation in decibels would be 10 log10(10-6 W/m2 / 10-12 W/m2).
Substituting the values, we get: β (dB) = 10 log10(106), which simplifies to β (dB) = 10 * 6 = 60 dB. Thus, the sound intensity level of the given sound intensity is 60 decibels.