Question

Brendan throws a rock into a pond. The bottom of the pond is 212.6 ft relative to the surface of the pond. Brendan is on a patio that is 2.7 ft above the surface of the pond. How many feet apart are Brendan and the rock?

Answer 1

To calculate the distance between Brendan and the rock, we add the depth of the pond (212.6 ft) to Brendan's height above the surface (2.7 ft), totaling 215.3 ft.

Step-by-step explanation:

The question is asking to calculate the distance between Brendan and the rock he throws into the pond. To find this distance, we need to consider the depth of the pond relative to its surface, plus the height of the patio above the surface of the pond where Brendan is standing when he throws the rock.

The bottom of the pond is 212.6 ft below the surface, and Brendan is standing 2.7 ft above the surface. To find the total distance between Brendan and the rock, we simply add these two distances together:

• 212.6 ft (depth of the pond) + 2.7 ft (height of Brendan above the surface) = 215.3 ft

Therefore, Brendan and the rock are 215.3 feet apart once the rock reaches the bottom of the pond.