Final answer:
To calculate the mass in grams of a sample of Ag containing 1.97 x 10²² atoms, we use Avogadro's number and the molar mass of silver (Ag). We find that the mass of the sample is 3.53 grams of Ag.
Step-by-step explanation:
To calculate the mass in grams of a sample of Ag containing 1.97 x 10²² atoms, we need to use the concept of mole and Avogadro's number. Avogadro's number is 6.022 x 10²³ atoms per mole. So, first we calculate the number of moles of Ag atoms:
1 mole Ag = 6.022 x 10²³ atoms Ag
1.97 x 10²² atoms Ag x (1 mole Ag / 6.022 x 10²³ atoms Ag) = 0.0327 moles Ag
Next, we use the molar mass of silver (Ag) to convert moles to grams:
Molar mass of Ag = 107.9 g/mol
0.0327 moles Ag x 107.9 g/mol = 3.53 grams Ag