Answer:
216.5 amu
Step-by-step explanation:
Step 1: Given data
- Mass of isotope ²¹⁵X (m²¹⁵X): 215 amu
- Abundance of isotope ²¹⁵X (ab²¹⁵X): 25%
- Mass of isotope ²¹⁷X (m²¹⁷X): 217 amu
- Abundance of isotope ²¹⁷X (ab²¹⁷X): 75%
Step 2: Calculate the average atomic mass for the element
When an element has 2 or more isotopes, we calculate the average atomic mass (am) using the following expression.
am = ∑ mi × abi / 100%
where,
mi: mass of each isotope
abi: abundance of each isotope
am = (m²¹⁵X × ab²¹⁵X + m²¹⁷X × ab²¹⁷X) / 100%
am = (215 amu × 25% + 217 amu × 75%) / 100% = 216.5 amu