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According to molecular orbital theory, the twelve outermost electrons in the O2 molecule are distributed as follows:

a. 2 in sigma bonding, 10 in pi bonding
b. 4 in sigma bonding, 8 in pi bonding
c. 6 in sigma bonding, 6 in pi bonding
d. 8 in sigma bonding, 4 in pi bonding

User Tospo
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Final answer:

According to molecular orbital theory, the distribution of the twelve outermost electrons in the O2 molecule is 4 in sigma bonding and 8 in pi bonding. This results in the O2 molecule having two unpaired electrons.

Step-by-step explanation:

According to molecular orbital theory, the twelve outermost electrons in the O2 molecule are distributed as follows: b. 4 in sigma bonding, 8 in pi bonding. In the molecular orbital energy-level diagram for O2, there are only 2 electrons to place in the (p, Tp) pair of orbitals, and according to Hund's rule, one electron occupies each orbital. This results in the O2 molecule having two unpaired electrons.

User GalahadXVI
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