Final answer:
Using VSEPR theory, the smallest bond angle in BrF3 is predicted to be 90 degrees, derived from the T-shaped molecular geometry with trigonal bipyramidal electronic geometry.
Step-by-step explanation:
To predict the smallest actual bond angle in BrF3 using the VSEPR theory, one must first understand the electronic geometry of the molecule. BrF3 has a total of five electron pairs around bromine (three bonding pairs and two lone pairs). The molecular geometry that minimizes repulsion in such a case is referred to as T-shaped, which is derived from the trigonal bipyramidal electronic geometry where the lone pairs occupy equatorial positions to reduce repulsion. Consequently, the smallest bond angles in BrF3 are between the axial and equatorial positions. In a trigonal bipyramidal geometry, these angles are 90 degrees.
Thus, according to VSEPR theory, the smallest actual bond angle in BrF3 is A) 90 degrees.