Question

Ack needs to hire someone to feed and walk his dogs while he is away on a business trip. his neighbor said that she can do it for $40 per day. he also found a pet-sitting company that charges $25 per day, plus a $75 registration fee. which equation can you use to find d, the number of days the trip would need to last for the two options to cost the same? how many days would the trip need to last for the two options to cost the same?

Answer 1

Ack can use the equation 40d = 25d + 75 to determine that his business trip needs to last 5 days for the costs of hiring his neighbor and the pet-sitting company to be the same.

Step-by-step explanation:

To determine when the cost of hiring the neighbor and the pet-sitting company would be the same, we set up an equation with d representing the number of days Ack's trip would last. The neighbor's cost is $40 per day, so the total cost for the neighbor is 40d. The pet-sitting company's cost is $25 per day plus a $75 registration fee, which gives us a total cost of 25d + 75. By setting the two costs equal to each other, we get the equation 40d = 25d + 75. To solve for d, we subtract 25d from both sides of the equation, which gives us 15d = 75. Then, by dividing both sides by 15, we find that d = 5. Therefore, Ack's trip would need to last 5 days for the cost of the neighbor and the pet-sitting company to be the same.