Final answer:
To calculate the ball's velocity at the instant of release, the horizontal velocity value from the provided graph is needed, which is constant until the time of release at 0.7 seconds; however, the exact value is not given. The vertical velocity begins at 4.90 m/s and is influenced by gravity but does not give the exact velocity at release.
Step-by-step explanation:
The question concerns the velocity of the baseball at the instant of release, assuming it started from rest. Given that the horizontal velocity is constant, the velocity at release is simply the value of this horizontal velocity. To determine this, we need the specific value from the horizontal velocity-time graph. However, as it is not provided in the information above, we cannot calculate the exact velocity. Instead, we can infer that the ball was moving at a certain horizontal velocity that remained constant from the time the pitcher started the motion until the release of the ball at 0.7 seconds.
The vertical velocity information indicates the ball's vertical speed begins at 4.90 m/s, changes due to the acceleration due to gravity (-9.8 m/s2), and crosses through zero at 0.55 seconds. However, since the release apparently occurs at 0.7 seconds, the exact velocity at the point of release in the vertical direction is not provided. It would typically require more information or would be the final velocity in the vertical graph provided.