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If the volume of the original sample in part a ( p1 = 902 torr , v1 = 20.0 l ) changes to 54.0 l , without a change in the temperature or moles of gas molecules, what is the new pressure, p2 ?

User Rakibtg
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Final answer:

Using Boyle's Law, the new pressure (p2) is calculated to be approximately 334.1 torr when the volume of a gas sample changes from 20.0 L to 54.0 L, assuming constant temperature and moles of gas.

Step-by-step explanation:

The student's question pertains to the application of Boyle's Law in Chemistry, which states that at constant temperature, the pressure of a given amount of gas is inversely proportional to its volume. Given the initial conditions of the gas sample (p1 = 902 torr and v1 = 20.0 L), and the change in volume to 54.0 L without a change in temperature or moles of gas, we can find the new pressure (p2).

Calculating p2 Using Boyle's Law

Boyle's Law is represented by the equation p1v1 = p2v2. To calculate p2, rearrange the equation:

p2 = (p1v1) / v2

Substitute in the known values:

p2 = (902 torr × 20.0 L) / 54.0 L

We can now perform the calculation:

p2 = 18040 torr· L / 54.0 L

p2 = 334.074 torr

Thus, the new pressure p2 when the volume changes to 54.0 L, without a change in temperature or moles of gas, is approximately 334.1 torr.

User Lukasvo
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