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If 3.6 moles of Al and 3.1 moles of Fe2O3 are allowed to react, what is the maximum number of moles of Al2O3 that can be produced?

2 Al + Fe2O3 → Al2O3 + 2 Fe

User Bmhkim
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Final answer:

To calculate the maximum number of moles of Al2O3 produced when 3.6 moles of Al and 3.1 moles of Fe2O3 react, multiply the number of moles of Al by the stoichiometric ratio of Al to Al2O3 in the balanced chemical equation.

Step-by-step explanation:

To determine the maximum number of moles of Al2O3 that can be produced when 3.6 moles of Al and 3.1 moles of Fe2O3 react, we need to compare the stoichiometric ratio of Al to Al2O3 in the balanced chemical equation. In the balanced equation, 2 moles of Al react with 1 mole of Fe2O3 to produce 1 mole of Al2O3. Therefore, we can calculate the maximum number of moles of Al2O3 by multiplying the number of moles of Al by the stoichiometric ratio:

Number of moles of Al2O3 = 3.6 moles Al × (1 mole Al2O3 / 2 moles Al) = 1.8 moles Al2O3

User Evgenii Bazhanov
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