Question

How many moles of KCl are present in 95.3 ml of 2.10 M KCl?

Options:
Option 1: 0.200 moles
Option 2: 0.100 moles
Option 3: 0.020 moles
Option 4: 0.021 moles

Answer 1

The number of moles of KCl in 95.3 mL of 2.10 M KCl is 0.200 moles.

Step-by-step explanation:

To determine the number of moles of KCl present in a solution, we can use the formula:

moles = concentration (M) x volume (L)

In this case, the concentration is 2.10 M and the volume is 95.3 mL. However, the volume needs to be in liters, so we divide by 1000:

95.3 mL = 0.0953 L

Now we can calculate the moles:

moles = 2.10 M x 0.0953 L = 0.1998 moles

Rounding to the appropriate number of significant figures gives us:

0.200 moles