Final answer:
The final speed of an electron accelerated from rest through a voltage of 25.0 MV is 5.30 x 10^6 m/s.
Step-by-step explanation:
The final speed of an electron accelerated from rest through a voltage of 25.0 MV can be calculated using the equation:
v = √(2qV)/m
where:
- v is the final velocity of the electron
- q is the charge of the electron
- V is the voltage
- m is the mass of the electron
Plugging in the given values:
v = √[(2 × -1.60 × 10-19 C × 25.0 × 106 V) / (9.11 × 10-31 kg)] = 5.30 × 106 m/s
Therefore, the final speed of the electron is 5.30 × 106 m/s.