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Solve the equation 2x^2+x-31=0 to the nearest tenth

User Zep
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1 Answer

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Final answer:

The nearest tenth solution of the equation 2x^2 + x - 31 = 0is 3.5.

Step-by-step explanation:

To solve the equation 2x^2 + x - 31 = 0 to the nearest tenth, we can use the quadratic formula.

For an equation of the form ax^2 + bx + c = 0, the quadratic formula is x = (-b +/- sqrt(b^2 - 4ac)) / (2a).

Applying this formula to our equation, where a = 2, b = 1, and c = -31, we get:

x = (-1 +/- sqrt(1^2 - 4(2)(-31))) / (2(2))

x = (-1 +/- sqrt(1 + 248)) / 4

x = (-1 +/- sqrt(249)) / 4

Using a calculator, we find that the two possible solutions to the equation are approximately -4.5 and 3.5. To the nearest tenth, the solution is 3.5.

User Chicky
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