Final answer:
To prepare 3.00 L of a 0.500 M CaCl2 solution from a 10.0 M stock solution, you need to dilute 150 mL of the stock solution with water to reach the total volume of 3.00 L.
Step-by-step explanation:
To prepare 3.00 L of a 0.500 M CaCl2 solution from a 10.0 M stock solution, you can use the dilution formula M1 × V1 = M2 × V2 where M1 and V1 are the molarity and volume of the stock solution, respectively, and M2 and V2 are the molarity and volume of the diluted solution, respectively. Plug in the known values, M1 = 10.0 M, M2 = 0.500 M, and V2 = 3.00 L, and solve for V1, which is the volume of stock solution needed:
10.0 M × V1 = 0.500 M × 3.00 L
V1 = (0.500 M × 3.00 L) / 10.0 M
V1 = 0.150 L or 150 mL
Therefore, you will need to mix 150 mL of the 10.0 M stock solution with enough water to make a total volume of 3.00 L to achieve a 0.500 M diluted solution of calcium chloride.