Question

How many millimoles of Ca(NO3)2 contain 4.78x10^22 formula units of Ca(NO3)2?

Options:
a) 1.46 millimoles
b) 2.91 millimoles
c) 4.78 millimoles
d) 9.56 millimoles

Answer 1

The number of millimoles of Ca(NO3)2 containing 4.78x10^22 formula units of Ca(NO3)2 is 2.91 millimoles.

Step-by-step explanation:

To find the number of millimoles of Ca(NO3)2 containing 4.78x10^22 formula units of Ca(NO3)2, we need to use the molar mass of Ca(NO3)2. The molar mass of Ca(NO3)2 is calculated by adding the atomic masses of calcium, nitrogen, and oxygen. The molar mass of Ca(NO3)2 is 164.008 g/mol.

Now, we can use the molar mass to convert the number of formula units to millimoles. To do this, we divide the number of formula units by Avogadro's number (6.022x10^23) to get the number of moles and then multiply by 1000 to convert to millimoles.

So, the number of millimoles of Ca(NO3)2 containing 4.78x10^22 formula units of Ca(NO3)2 is 2.91 millimoles (approximately).