Question

What volume of a 3.0 x 10⁻³ M solution is needed to prepare 50.0 mL of a 5.0 x 10⁻⁵ M solution, and how many moles of solute are in this solution?

A) 0.5 mL and 2.5 x 10⁻⁸moles
B) 50.0 mL and 5.0 x 10⁻⁷ moles
C) 0.05 mL and 2.5 x 10⁻⁷ moles
D) 0.5 mL and 2.5 x 10⁻⁷ moles"

Answer 1

The volume of a 0.575-M glucose solution that can be prepared from 50.00 mL of a 3.00-M glucose solution is approximately 260.87 mL.

Step-by-step explanation:

To determine the volume of a 0.575-M solution of glucose that can be prepared from 50.00 mL of a 3.00-M glucose solution, we can use the formula:

M1V1 = M2V2

Where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.

Using the given values, we can rearrange the formula:

V2 = (M1 x V1) / M2 = (3.00 M x 50.00 mL) / 0.575 M = 260.87 mL

Therefore, the volume of the 0.575-M glucose solution that can be prepared from 50.00 mL of the 3.00-M solution is approximately 260.87 mL.